BTG problem 700+ discussion (2)

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BTG problem 700+ discussion (2)

by Night reader » Sun Jan 02, 2011 9:23 pm
The points A(0, 0), B(0, 4a - 5) and C(2a + 1, 2a + 6) form a triangle. If angle ABC=90`, what is the area of triangle ABC?

A. 102
B. 120
C. 132
D. 144
E. 156

[spoiler]this was extracted from the BTG problem set; the official explanation suggests drawing an arbitrary line AB which is horizontal and setting y coordinates for the points B and C as equal. Instead, I look into the slop relationship of lines B and C since the two must form an angle and their line directions must be opposite which means crossing of lines B and C at some point to form the vertice => now we may set y-coordinates as equal for B and C!

p.s. this problem could be complicated by drawing multiple lines in the xy-rectangular coordinate system and having all lines be related with themselves - the approach of arbitrary line(s) would not fit then[/spoiler]
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by Anurag@Gurome » Sun Jan 02, 2011 9:54 pm
Night reader wrote:The points A(0, 0), B(0, 4a - 5) and C(2a + 1, 2a + 6) form a triangle. If angle ABC=90`, what is the area of triangle ABC?

A. 102
B. 120
C. 132
D. 144
E. 156
Traditional method:
  • As angle B is the right angle, AB and BC are the adjacent sides of the right angle. Therefore, area of the triangle = (1/2)*AB*BC. Calculate the lengths of AB and BC in this. Replace a with its solution using the slope relationship, i.e. (Slope of AB)*(Slope of BC) = -1
Tricky method:
  • Note that point A is nothing but the origin and point B lies on the y-axis. Thus AB is a line segment on y-axis, whose one end is the origin. Therefore, BC must parallel to x-axis and hence y-coordinate of B and C will be same. Equating them, (4a - 5) = (2a + 6) => a = 11/2. Now Length of AB = (4a - 5) = 17 and length of BC = (2a + 1) = 12. Hence area of the triangle = (1/2)*12*17 = 102
The correct answer is A.
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by Night reader » Sun Jan 02, 2011 10:05 pm
Anurag, which method falls in my solution noted in the spoiler?

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by Anurag@Gurome » Sun Jan 02, 2011 11:24 pm
Night reader wrote:Anurag, which method falls in my solution noted in the spoiler?
I think second one as you have used same logic for equating the y-coordinates of B and C.
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