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either $40 or $80

by sanju09 » Tue Mar 03, 2009 4:57 am
Janice spent $200 at a shopping mall. How many items worth $40 did she purchase?

(1) All the items she purchased were worth either $40 or $80.

(2) She purchased more than one item worth $80.
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Re: either $40 or $80

by piyush_nitt » Tue Mar 03, 2009 5:17 am
sanju09 wrote:Janice spent $200 at a shopping mall. How many items worth $40 did she purchase?

(1) All the items she purchased were worth either $40 or $80.

(2) She purchased more than one item worth $80.
IMO C

1 . Not suff

3 Items - $40 + 1 item $80

OR

1 item $ 40 + 2 item $ 80

2. Not suff

No info about $40

price could be $100 , $ 90 etetetc

1 & 2 suff
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by shargaur » Tue Mar 03, 2009 7:29 am
Janice spent $200 at a shopping mall. How many items worth $40 did she purchase?

(1) All the items she purchased were worth either $40 or $80.

(2) She purchased more than one item worth $80.

1) Cost of items iteself doesnt convey anything
2) one more item of worth $80, other can be of $20 each..

so if both are there
then
40(x) + 80(x+1) = 200

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by lilu » Tue Mar 03, 2009 2:59 pm
I also think that the answer is C

Statement 1:
x-number of 40-dollar items purchased; y-number of 80-dollar items purchased:
40x+80y=200
two unknowns--> cannot tell how many 40-dollar items have been purchased
So A is insufficient

Statement 2:
We know that more than 1 80-dollar items have been purchased.
So it has to be 2, 3... items:
If there were two items, then:
80*2=160
If there were three items, then:
80*3=240, but a total of 200 dollars was spent. So, it has to be only 2 80-dollar items.
But we don't know how the rest 40 dollars were spent. She could have purchased 1 40-dollar item or 2 20-dollar items... or spent any other way.
So, B is also not sufficient.

Taking both statements together:
we know that two 80-dollar items were purchased and the only way she could spend the rest 40 dollars is by purchasing 1 40-dollar item.
So, A+B -->SUFF
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