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If s is the product of the integers from 100 to 200 inclusiv

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by imane81 » Wed Feb 10, 2010 12:16 pm
Thank you for answering this one...
If s is the product of the integers from 100 to 200 inclusive, and if t is the product of the integers from 100 to 201 inclusive, what is 1/s + 1/t in terms of t?
A. (201)^2/t
B. {(202)(201)}/t
C. 201/t
D. 202/t
E. {(202)(201)}/t^2
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by shashank.ism » Wed Feb 10, 2010 12:19 pm
imane81 wrote:Thank you for answering this one...
If s is the product of the integers from 100 to 200 inclusive, and if t is the product of the integers from 100 to 201 inclusive, what is 1/s + 1/t in terms of t?
A. (201)^2/t
B. {(202)(201)}/t
C. 201/t
D. 202/t
E. {(202)(201)}/t^2
S = 100...200
t = 100...201
t= s.201
1/s+1/t = 1/(t/201)+1/t = 201/t +1/t = [spoiler]202/t[/spoiler]
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by Scott@TargetTestPrep » Tue Dec 05, 2017 4:50 pm
imane81 wrote:Thank you for answering this one...
If s is the product of the integers from 100 to 200 inclusive, and if t is the product of the integers from 100 to 201 inclusive, what is 1/s + 1/t in terms of t?
A. (201)^2/t
B. {(202)(201)}/t
C. 201/t
D. 202/t
E. {(202)(201)}/t^2
We are given that s is the product of the integers from 100 to 200 inclusive and that t is the product of the integers from 100 to 201 inclusive. Thus, we know the following:

s x 201 = t

s = t/201

We must determine the value of 1/s + 1/t in terms of t. Since we know that s = t/201, we can substitute t/201 for s in the expression 1/s + 1/t:

1/(t/201) + 1/t

201/t + 1/t

202/t

Answer: D

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by Matt@VeritasPrep » Tue Dec 05, 2017 5:32 pm
s = 100 * 101 * ... * 199 * 200

t = 100 * 101 * ... * 199 * 200 * 201

t = s * 201

t/201 = s

so:

1/t + 1/s is the same as

1/t + 1/(t/201) is the same as

1/t + 201/t is the same as

202/t
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