BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Triangle problem

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Junior | Next Rank: 30 Posts
Posts: 18
Joined: Tue Mar 06, 2007 8:57 am
by gmatme » Sun Mar 18, 2007 7:52 am
Can someone explain why the answer is B?

The perimeter of a certain isoscles right triangle is 16 + 16sqrt(2). What is the lenght of the hypotenuse of the triangle?

A) 8
b) 16
c) 4sqrt(2)
d) 8sqrt(2)
e) 16sqrt(2)

Isn't that answer should be d? 1:1:sqrt(2) so 8:8:8sqrt(2)?
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |
Newbie | Next Rank: 10 Posts
Posts: 1
Joined: Mon Feb 12, 2007 10:16 am
Location: India

by jaskaran_d » Sun Mar 18, 2007 8:06 am
Perimeter of an isosceles right angle triangle is x(sqrt(2) + 2) where x is the lenght of the equal side.

therefore, x(sqrt(2) + 2)= 16 + 16sqrt(2) and x = (16 + 16sqrt(2))/(sqrt(2) + 2)

Lenght of hypotenues is x* sqrt(2)

Hence, length of hypo= {(16 + 16sqrt(2))* sqrt(2)}/(sqrt(2) + 2)

Ans is 16
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Junior | Next Rank: 30 Posts
Posts: 18
Joined: Tue Mar 06, 2007 8:57 am

by gmatme » Sun Mar 18, 2007 8:21 am
Got it thanks!
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 559
Joined: Tue Mar 27, 2007 1:29 amFollowed by: 2 members
Thanked: 5 times

by Cybermusings » Wed Mar 28, 2007 6:55 am
The perimeter of a certain isoscles right triangle is 16 + 16sqrt(2). What is the lenght of the hypotenuse of the triangle?

A) 8
b) 16
c) 4sqrt(2)
d) 8sqrt(2)
e) 16sqrt(2)

Great Solution...Thanks Jaskaran!!!!
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1