How is the following simplification done:
2^100-2^96
2^96*(2^4-1) (This is the step I do not get)
2^96*(16-1)
15*2^96
2^96*3*5.
How is 2^11 turned into 2^(4-1) and then multiplied against 2^96? Is there a general rule?
thanks
2^100-2^96
2^96*(2^4-1) (This is the step I do not get)
2^96*(16-1)
15*2^96
2^96*3*5.
How is 2^11 turned into 2^(4-1) and then multiplied against 2^96? Is there a general rule?
thanks
