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by pappueshwar » Wed Mar 14, 2012 10:03 am
In arranging alphabet letters, CIRCLE, how many times does at least one letter stand between C and C?

A. 180 B. 200 C. 210 D. 240 E. 250

OA IS D
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by Neo Anderson » Wed Mar 14, 2012 10:20 am
TOTAL NO OF WAYS = NO OF WAYS WITH C&C NEXT TO EACH OTHER + NO OF WAYS WITH AT LEAST ONE LETTER B/N C&C
=> NO OF WAYS WITH AT LEAST ONE LETTER B/N C&C = TOTAL NO OF WAYS - NO OF WAYS WITH C&C NEXT TO EACH OTHER
TOTAL NO OF WAYS : 6! / 2! = 360
NO OF WAYS WITH C&C NEXT TO EACH OTHER: 5! = 120
NO OF WAYS WITH AT LEAST ONE LETTER B/N C&C: = 360 - 120 = 240

HENCE D
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