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SFtraveler
- Junior | Next Rank: 30 Posts
- Posts: 21
- Joined: Mon Aug 30, 2010 11:51 am
(1) p^2 > 0
(2) |p|-p > 0
there are three cases within statement (2) --> p>0, p=0 and p<0
a) p>0, p-p>0 here's no solution, as 0 cannot be greater than 0
b) p=0, 0-p>0, if p turns 0 then 0-0>0 ?, here's no solution
c) p<0, (-ve)p - (-ve)p>0, p cannot be greater than 0
none is viable, hence statement (2) is Not Sufficient
Combined statements (1&2) is either Not Sufficient
IOM [spoiler]E[/spoiler]
SFtraveler wrote:Is p positive?
1) The square of p is positive
2) |p| - p is positive

















