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GMAT prep - Coordinate Geometry

Expert replies
by akay » Fri Aug 10, 2007 7:12 am
Any ideas on solving this. Any formulas that one can use while solving coordinate geo. problems of this kind?

In the xy-coordinate system, if (a, b) and
(a + 3, b + k) are two points on the line defined by
the equation x = 3y – 7, then k =

(A) 9
(B) 3
(C) 7/3
(D) 1
(E) 1/3
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Source: — Problem Solving |

Re: GMAT prep - Coordinate Geometry

by gabriel » Fri Aug 10, 2007 7:34 am
akay wrote:Any ideas on solving this. Any formulas that one can use while solving coordinate geo. problems of this kind?

In the xy-coordinate system, if (a, b) and
(a + 3, b + k) are two points on the line defined by
the equation x = 3y – 7, then k =

(A) 9
(B) 3
(C) 7/3
(D) 1
(E) 1/3
well the formula is already given to you ..

substitute the values of x and y in the equation x = 3y-7 ... over here a=x and b =y ..

.. so we have a = 3b -7 .. (1)

Now, substituting the values (a+3,b+k) .. over here x = a+3 and y = b+k ..
so we have a+3 = 3(b+k)-7 .. a = 3b+3k-10 .... (2)

equating (1) and (2) we get 3b-7=3b+3k-10 .. that is 3k = 3 .. therefore k =1 ..
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Re: GMAT prep - Coordinate Geometry

by akay » Fri Aug 10, 2007 7:38 am
ok got it. appreciate your taking the time to help me.
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