BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

GMATPrep2

This topic has expert replies
Post new topic Post Reply
Previous Topic Next Topic
User avatar
Master | Next Rank: 500 Posts
Posts: 277
Joined: Sun Jun 17, 2007 2:51 pm
Location: New York, NY
Thanked: 6 times
Followed by:1 members

GMATPrep2

by givemeanid » Mon Aug 27, 2007 6:53 pm
If zy < xy < 0, is |x-z| + |x| = |z|?
1. z < x
2. y > 0

If you are in a rush, GMAT Traps will get ya!
So It Goes
Top
Source: — Data Sufficiency |
Senior | Next Rank: 100 Posts
Posts: 37
Joined: Sun Aug 26, 2007 3:45 pm
Thanked: 1 times

Re: GMATPrep2

by Jameschan168 » Mon Aug 27, 2007 7:41 pm
I think the answer is B.

From the question stem we can tell that x & z have to have the same sign. So the answer will depend on whether y > 0 or y <0.

Stmt 1 is insufficent since we don't know what y is.
For example, if y > 0 and x = -5 & z = -6, then abs (-5 + 6) + abs (-5) = abs (6), or simply 1 + 5 = 6, which is true.

However, if y < 0 and let's say x = 7 and z = 6, then abs (7-6) + abs (7) does not equal = abs (6).

Stmt 2 is sufficient based on the explanation above.

givemeanid wrote:If zy < xy < 0, is |x-z| + |x| = |z|?
1. z < x
2. y > 0

If you are in a rush, GMAT Traps will get ya!
Top
User avatar
Legendary Member
Posts: 986
Joined: Wed Dec 20, 2006 11:07 am
Location: India
Thanked: 51 times
Followed by:1 members

Re: GMATPrep2

by gabriel » Tue Aug 28, 2007 12:10 am
givemeanid wrote:If zy < xy < 0, is |x-z| + |x| = |z|?
1. z < x
2. y > 0

If you are in a rush, GMAT Traps will get ya!
...Me going for D ... from the first statement we get z<x, this means that both z and x are negative and that the magnitude of z is greater than x .. why? read this https://www.beatthegmat.com/viewtopic.php?t=4586 ...

... now, let z=-5 and x = -3 ... so mod(x-z)= 2, mod(x)=3 and mod(z)=5 .. so the statement holds true .. so statement one is sufficient ..
Top
Newbie | Next Rank: 10 Posts
Posts: 5
Joined: Mon May 21, 2007 7:10 am

by abhik » Tue Aug 28, 2007 4:16 am
What is the OA
Top
Master | Next Rank: 500 Posts
Posts: 101
Joined: Tue Aug 07, 2007 1:45 am
Followed by:1 members

by agps » Tue Aug 28, 2007 4:46 am
I would answer B.

from the question z<x if y>0
in 1) z<x then y<0 or y>0 depending on z and x being positive or negative (for z and x < 0 then y > 0 e.g. -2 and -1 y>0, for z and x > 0 then y < 0 e.g. 1 and 2 y>0), not sufficient because, if z = 1 and x = 2, |2-1|+2 = 3 different from 1 and if z=-2 and x=-1 |-1-(-2)|+|-1|= 2 equal to |-2|
in 2) if y> 0 then z and x < 0, for z=-1/2 and x=-1/4, |-1/4-(-1/2)|+|-1/4| =1/4+1/4 = 1/2 = |z|.
Top
User avatar
Master | Next Rank: 500 Posts
Posts: 277
Joined: Sun Jun 17, 2007 2:51 pm
Location: New York, NY
Thanked: 6 times
Followed by:1 members

by givemeanid » Tue Aug 28, 2007 5:58 am
If zy < xy < 0, is |x-z| + |x| = |z|?
1. z < x
2. y > 0


OA is D.

First realize that, both statements are giving you the same information. (I missed this critical part when I was taking the test since stmt 1 does not mention y and stmt 2 does not mention x and z, I rushed to a conclusion that either C or E should be the right choice. My bad.)

1. Since zy < xy and z < x, y > 0 (same as stmt 2)
Now, x > z, so |x-z| = x-z
Also zy < xy < 0 and y > 0
So z < x < 0
|x| = -x
|z| = -z

Now,
|x-z| + |x| ? |z|
x - z -x ? -z
0 = 0. So, true.
SUFFICIENT.

2. The reasoning above applies to stmt 2.


Hence, D
So It Goes
Top
User avatar
Legendary Member
Posts: 986
Joined: Wed Dec 20, 2006 11:07 am
Location: India
Thanked: 51 times
Followed by:1 members

by gabriel » Tue Aug 28, 2007 6:47 am
agps wrote:I would answer B.

from the question z<x if y>0
in 1) z<x then y<0 or y>0 depending on z and x being positive or negative (for z and x < 0 then y > 0 e.g. -2 and -1 y>0, for z and x > 0 then y < 0 e.g. 1 and 2 y>0), not sufficient because, if z = 1 and x = 2, |2-1|+2 = 3 different from 1 and if z=-2 and x=-1 |-1-(-2)|+|-1|= 2 equal to |-2|
in 2) if y> 0 then z and x < 0, for z=-1/2 and x=-1/4, |-1/4-(-1/2)|+|-1/4| =1/4+1/4 = 1/2 = |z|.
Thats where ur wrong .. if z<x then z and x both have to be negative and y > 0 ... as givemeaind has written in his post if u correctly analyze both the statements then you will realize that they both give then same information ( that is y > 0 ) .. tricky question btw ..
Top
Master | Next Rank: 500 Posts
Posts: 101
Joined: Tue Aug 07, 2007 1:45 am
Followed by:1 members

by agps » Tue Aug 28, 2007 8:10 am
you're right.
what i forgot was that if y<0 both z and x > 0, but z > x.
(y = -1, z=2 and x=3 zy=-2 > xy=-3, contradicts the stem)
statement 1 says z < x, therefore y > 0
Top
Post new topic Post Reply
• Page 1 of 1