How many number of 3 digit numbers can be formed with the digits 0,1,2,3,4,5 if no digit is repeated in any number? How many of these are even and how many odd?
The total number of 3 digit numbers would be:
First digit can be 5 different ways (It can't be 0)
The second digit can also be 5 ways (it can be 0)
The last digit can be 4 ways.
5 5 4
5*5*4=100
100 Total 3 digit numbers using 0,1,2,3,4,5
Now the number of odd numbers: The ones digit is 1,3, or 5.
The first digit can be 4 different ways (it can't be 0 and can't be the odd digit that is the ones digit)
The second digit can be 4 different ways (it can be 0 but can't be the first digit or the odd digit that is the ones digit)
The last digit can be 3 different ways (1,3, or 5)
4 4 3
4*4*3=48
So there are 48 odd digits.
The number of even digits will be 100-48 = 52
52 even digits
4 4 3
