--------------------------------------------------------------------------------------ketkoag wrote:If each of the 12 teams participating in a certain tournament plays exactly one game
with each of the other teams, how many games will be played?
A. 144 B. 132 C. 66 D. 33 E. 23
No. of ways in which 12th team can play uniquely only once is 11
No. of ways in which 11th team can play uniquely only once is 10
.
.
.
No. of ways in which 2nd team can play uniquely only once is 1
=> Total no. of ways are 11+10+9+8+7+6+5+4+3+2+1 = 11*12/2 = 66 ways.
Thus, C
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Please correct if wrong.
