BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem
TTP OnDemand GMAT Video Course
Featured Course

Target Test Prep GMAT OnDemand

Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.

  • 715+ score guarantee — highest in the industry (99th percentile)
  • 52 chapters · 1,500+ lessons · 4,000+ practice questions
  • 400 hours of video · 1,500+ instructor-led HD smartboard lessons
  • 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
  • 24/7 live support + weekly Zoom office hours with GMAT instructors
  • TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
  • 1,200+ flashcards + AI-powered study assistant & daily calendar
  • OnDemand, LiveTeach & GMAT Bootcamp formats available
  • Also: GRE, SAT Math & Executive Assessment courses
  • MBA Admissions Consulting now available
  • 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
  • 200,000+ students served
  • 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★ 5.0 (559 reviews)
130-pt guarantee
$0 to start then $127/mo
Start Free 5-Day Trial Read 559 Reviews →

Math doubts - help

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Source: — Problem Solving |
Master | Next Rank: 500 Posts
Posts: 175
Joined: Mon Jul 02, 2007 12:01 pmFollowed by: 1 member
Thanked: 15 times

by jangojess » Sun Oct 21, 2007 7:59 pm
1) y km/hr = y * 1000 m/60*60 s = 5y/18 m/s = x m/s

So y = 18x/5

2) y=3x+2....now if a point (r,s) is present in the line then this equation has to be satisfied for that point...ie s=3r+2 has to be satisfied or 3r-s+2 = 0

Now if u see in both stmts we have prod of 2 equations equalled to 0 which means any of terms can be zero. If we combine them we can get 3r-s+2 = 0....Ans is C
Trying hard!!!
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Junior | Next Rank: 30 Posts
Posts: 19
Joined: Sun Feb 11, 2007 3:05 pm

by Caps » Mon Oct 22, 2007 12:31 am
Sorry but didn't understand the second answer...
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 175
Joined: Mon Jul 02, 2007 12:01 pmFollowed by: 1 member
Thanked: 15 times

by jangojess » Mon Oct 22, 2007 5:49 am
if a point lies in and equation then that equation has to be satisfied with the value of the co-ordinates of that point....u can take any linear equation and verify using different values of co-ordinates. In our case if the point (r,s) lies on the line y=3x+2 then s=3r+2 or 3r-s+2 = 0....i hope u have understood this part. Now we need to prove whether 3r-s+2 is 0 or not

stmt 1 - expression 1 * expression 2 = 0 which means either expression can have a value of 0. So insuff

Stmt 2 - same explanation as stmt1....any expression can have a value 0...so insuff

both - we can see that only one expression is in common and that is 3r-s+2 and this has to be zero for both expressions to be zero....So ans is C..
Trying hard!!!
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Junior | Next Rank: 30 Posts
Posts: 19
Joined: Sun Feb 11, 2007 3:05 pm

by Caps » Mon Oct 22, 2007 6:18 am
Of course... got it....

tnks a lot
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1