BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

if k is a positive Integer,how many unique Prime Factors Doe

Expert replies
Source: — Data Sufficiency |

by GMATinsight » Sat May 20, 2017 7:33 pm
ziyuenlau wrote:If k is a positive Integer, how many unique Prime Factors Does 14k have ?

(1) k^4 is divisible by 100
(2) 50*k has 2 Prime Factors

OA=C
to find the total prime factors of 14k we need to know the prime factors of k

Statement 1: k^4 is divisible by 100

this statement only confirms that k has ATLEAST two prime factors 2 and 5 but we do NOT know what other prime factors k may have hence
NOT SUFFICIENT

Statement 2: 50*k has 2 Prime Factors
50 k has two prime factors confirms that 50k has 2 and 5 but we don't know whether these two prime factors are available in k as well or not because they are available from 50 as well. But we realize that k has no prime factor other than 2 and 5 hence
NOT SUFFICIENT

Combining the two statements

We know that k has only two prime factors 2 and 5 hence
SUFFICIENT

Answer: Option C
"GMATinsight"Bhoopendra Singh & Sushma Jha
Most Comprehensive and Affordable Video Course 2000+ CONCEPT Videos and Video Solutions
Whatsapp/Mobile: +91-9999687183 l [email protected]
Contact for One-on-One FREE ONLINE DEMO Class Call/e-mail
Most Efficient and affordable One-On-One Private tutoring fee - US$40-50 per hour
Join the discussion

by ceilidh.erickson » Sun May 21, 2017 2:45 pm
hazelnut01 wrote:If k is a positive Integer, how many unique Prime Factors Does 14k have ?

(1) k^4 is divisible by 100
(2) 50*k has 2 Prime Factors

OA=C
First, REPHRASE the question:
We know how many unique prime factors 14 has: two (2 and 7). It would not be enough to know how many unique prime factors k has, since k may also contain factors of 2 or 7. These wouldn't be unique.

Target question: how many prime factors other than 2 or 7 does k have?


(1) k^4 is divisible by 100
Knowing one thing that a number is divisible by gives us only partial information. We know that it contains at least a 2 and a 5, but we don't know what else it may or may not be divisible by.

(2) 50*k has 2 Prime Factors
As GMATinsight points out, this tell us that k has no factors *other than* 2 and 5, but it could contain both, only one of the two, or neither (if k = 1). This doesn't give us enough to answer the question:
- if k contains 2 and 5, 14k will have 3 unique factors: 2,5, 7
- if k contains a 5 only, 14k will have 3 unique factors: 2,5, 7
- if k contains a 2 only, 14k will have 2 unique factors: 2,7
- if k contains neither (k = 1), 14k will have 2 unique factors: 2,7

Together:
k must contain a 2 and a 5 (per stmt 1), but if does not contain any other factors (per stmt 2). Therefore, 14k must contain unique factors of only 2, 5, and 7. Sufficient.

What is the source of this question? You must always post your sources - it is a copyright violation not to do so.
Ceilidh Erickson
EdM in Mind, Brain, and Education
Harvard Graduate School of Education
Join the discussion

by ceilidh.erickson » Mon Jun 05, 2017 7:12 pm
hazelnut01, following up - what is the source of this question?
Ceilidh Erickson
EdM in Mind, Brain, and Education
Harvard Graduate School of Education
Join the discussion