# (2a² + b)(x + y) + (a + b)(x - y)gmatpup wrote:If a = 1 and b = -2, then (2a^2 + b)(x+y) + (a+b)(x-y)=
= (2 - 2)(x + y) + (1 - 2)(x - y)
= 0 + (-1)(x - y)
= -(x - y)
= (y - x)
The correct answer is C.
If a=1 and b=-2...
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Anurag@Gurome
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= (2 - 2)(x + y) + (1 - 2)(x - y)
= 0 + (-1)(x - y)
= -(x - y)
= (y - x)
The correct answer is C.
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gmatpup
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Anurag@Gurome wrote:# (2a² + b)(x + y) + (a + b)(x - y)gmatpup wrote:If a = 1 and b = -2, then (2a^2 + b)(x+y) + (a+b)(x-y)=
= (2 - 2)(x + y) + (1 - 2)(x - y)
= 0 + (-1)(x - y)
= -(x - y)
= (y - x)
The correct answer is C.
I apologize if this sounds silly, but may I ask how you went from -(x-y) to (y-x) ? That is the difficulty I am having.
Thanks so much!!!
