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Pradeep,pbanavara wrote:If p,q,r, and s are nonzero numbers, is
(p – 1)(q - 2)2(r – 3)3(s – 4)4 ≧ 0?
(1) q > 2 and s > 4
(2) p > 1 and r > 3
How do you guys go about solving such problems ? Plugging in actual values seemed to take a lot of time ..
- pradeep
Thanks - That helps : The question is actuallylogitech wrote:Pradeep,pbanavara wrote:If p,q,r, and s are nonzero numbers, is
(p – 1)(q - 2)2(r – 3)3(s – 4)4 ≧ 0?
(1) q > 2 and s > 4
(2) p > 1 and r > 3
How do you guys go about solving such problems ? Plugging in actual values seemed to take a lot of time ..
- pradeep
if you look at the statement you will see how they match with the question stem
q>2 hmmm so it means q-2 > 0 right ?
Please apply this hint to the rest of the questions and see what you got. If you get stucked somewhere post your solution and I will be more than happy to help you.
Cramya will proud of me today!
Stop my man:stop@800 wrote:(q-2)^2 and (s-4)^4 will always be greater than 0
so we can ignore this part
we need to test
(p – 1)(r – 3)3 ≧ 0
A
no info for p and r
so insuff
B
p>1
and r>3
so
(p – 1)(r – 3)3 >0
hence suff
soa and is B
U bet I am. I am almost in tears after seeing your efforts to explain.....Cramya will proud of me today!
That's right my man!! YOU GOT IT!pbanavara wrote:Thanks - That helps : The question is actuallylogitech wrote:Pradeep,pbanavara wrote:If p,q,r, and s are nonzero numbers, is
(p – 1)(q - 2)2(r – 3)3(s – 4)4 ≧ 0?
(1) q > 2 and s > 4
(2) p > 1 and r > 3
How do you guys go about solving such problems ? Plugging in actual values seemed to take a lot of time ..
- pradeep
if you look at the statement you will see how they match with the question stem
q>2 hmmm so it means q-2 > 0 right ?
Please apply this hint to the rest of the questions and see what you got. If you get stucked somewhere post your solution and I will be more than happy to help you.
Cramya will proud of me today!
(p – 1)(q - 2)^2(r – 3)^3(s – 4)^4 ≧ 0?
Stmnt 1 : q-2 > 0 and s-4 > 0 => p -1 could be < 0 and r-3 < 0
so the value of the equation could be >0 <0 or =0
Stmnt 2 : r-1 >0 and s-3 > 0 implies the product has to be >= 0 because no matter what value q and s have they will be positive.
So the answer is B - which is the OA btw
Sorry, Actually when I started replying your reply was not therelogitech wrote:Stop my man:stop@800 wrote:(q-2)^2 and (s-4)^4 will always be greater than 0
so we can ignore this part
we need to test
(p – 1)(r – 3)3 ≧ 0
A
no info for p and r
so insuff
B
p>1
and r>3
so
(p – 1)(r – 3)3 >0
hence suff
soa and is B
1) You ruined the poster's homework
I think its clear now...2) How did you come up with (q-2)^2 and (s-4)^4 ?
:roll:
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