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Source: — Data Sufficiency |
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by shovan85 » Sat Oct 30, 2010 6:57 am
replayyyy wrote:Of the 60 animals in a certain farm, 2/3 are either pigs or cows. How many of the animals are cows?
(1) the farm has more than twice as many cows as it has pigs
(2) the farm has more than 12 pigs.
P + C = 60 * 2/3 = 40

1. C > 2P
let P = 10 then C = 30
let P = 11 then C = 29
.. So multiple chances. Thus NS.

2. P > 12
let P = 13 then C = 27
let P = 14 then C = 26
let P = 15 then C = 25
.. So multiple chances. Thus NS.

Combining both only P = 13 then C = 27 will satisfy.
P = 13 2P = 26 < 27 =C thus satisfied.

PS: No more other chances try with 14 it will not satisfy A :)
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by Night reader » Sat Oct 30, 2010 11:43 am
replayyyy wrote:Of the 60 animals in a certain farm, 2/3 are either pigs or cows. How many of the animals are cows?
(1) the farm has more than twice as many cows as it has pigs
(2) the farm has more than 12 pigs.
assign properties to problem and conditions 1, 2

problem c+p = 40
condition (1) c > 2p
condition (2) p > 12


solve inequalities (1) p < c/2; (2) 12 < p; 12 < p < c/2.
p must be integer (split pigs?) p=13
solve for c, c > 2p, c > 26, c = 27

plug into problem c + p = 40, 13 + 27 = 40

with both conditions the problem can be solved.

p.s. MGMAT tips for DS
My knowledge frontiers came to evolve the GMATPill's methods - the credited study means to boost the Verbal competence. I really like their videos, especially for RC, CR and SC. You do check their study methods at https://www.gmatpill.com
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