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GMAT PREP 1

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Master | Next Rank: 500 Posts
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by pkw209 » Tue Dec 29, 2009 10:13 am
Hey all,
Was able to figure this one out through backsolving but can someone provide a brief explanation on how you compute and solve for the hypotenuse? Thanks!

4) Perimeter of isosceles right triangle is 16 +16√2, what is hypotenuse?

a. 8
b. 16
c. 4√2
d. 8√2
e. 16√2
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by ace_gre » Tue Dec 29, 2009 11:27 am
Isosceles right triangle have sides as x, x and √2x.
We need to find out hypotenuse √2x

Perimeter = 2x+√2x=16+16√2.
Solving for √2x,
√2x(√2+1)=16(√2+1)

√2x=16==>hypotenuse. Answer is B
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by pkw209 » Wed Dec 30, 2009 12:31 pm
Awesome, thanks!
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