5 * 124 = 620
Consider the arrangement
A B 140 D E
To maximize A , we need to minimize D & E
minimum value of D = min val of E = 140
140 * 3 = 420
620 - 420 = 200
Now we need to distribute 200 between A & B such that A <= B <= 140
therefore A = B = 200/2 = 100
What is the OA ?
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onedayi'll
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5 pieces of wood
124 = mean
140 = median or the middle value
we need to find the maximum possible value therefore, minimize all the other values
the shortest piece of the wood has to be less than 140, largest has to be greater than 140.
total = 124*5 = 620
x + y + 140 + 140 + 140 = 620
x+y = 620-140*3 = 620-420
x+y = 200
Maximum possible length = 200/2 = 100.
124 = mean
140 = median or the middle value
we need to find the maximum possible value therefore, minimize all the other values
the shortest piece of the wood has to be less than 140, largest has to be greater than 140.
total = 124*5 = 620
x + y + 140 + 140 + 140 = 620
x+y = 620-140*3 = 620-420
x+y = 200
Maximum possible length = 200/2 = 100.
