dreamv wrote:x, 3, 1, 12, 8
If x is an integer, is the median of the 5 numbers shown greater than the average of the 5 numbers?
1) x>6
2) x is greater than the median of the 5 numbers
Look for values that satisfy both statements.
Be sure to try extreme values.
If x=9:
The numbers are 1, 3, 8, x=9, 12.
Average = (1+3+8+9+12)/5 = 33/5.
Median = 8.
Average < median.
If x=100:
The numbers are 1, 3, 8, 12, x=100.
Average = (1+3+8+12+100)/5 = 124/5.
Median = 8.
Average > median.
Since in the first case the average is less than the median, and in the second case the average is greater than the median, the two statements combined are INSUFFICIENT.
The correct answer is
E.
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