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easy question ratios

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by canuckclint » Tue Nov 04, 2008 10:26 pm
At the beginning of the year, the ratio of juniors to seniors in high school X was 3 to 4. During the year, 10 juniors and twice as many seniors transferred to another high school, while no new students joined high school X. If, at the end of the year, the ratio of juniors to seniors was 4 to 5, how many seniors were there in high school X at the beginning of the year?

answer: 120
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Source: — Problem Solving |

by parallel_chase » Tue Nov 04, 2008 11:51 pm
J/S = 3/4

4J = 3S
J = 3S/4

(J-10)/(S-20) = 4/5

5J - 50 = 4S - 80

4S - 5J = 30

4S - 15S/4 = 30

16S - 15S = 120

S =120

Hope this helps.
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Re: easy question ratios

by logitech » Tue Nov 04, 2008 11:52 pm
canuckclint wrote:At the beginning of the year, the ratio of juniors to seniors in high school X was 3 to 4. During the year, 10 juniors and twice as many seniors transferred to another high school, while no new students joined high school X. If, at the end of the year, the ratio of juniors to seniors was 4 to 5, how many seniors were there in high school X at the beginning of the year?

answer: 120
Juniors: 3X
Seniors: 4X

so you can have the 3/4 ratio

(3x-10)/(4x-20) = 4/5 ( twice as many as Juniors, 10x2=20)

X=30

Seniors: 4X : 120
LGTCH
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by raunekk » Wed Nov 05, 2008 3:34 am
same explanation as logitech....

ans 120
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