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gmattesttaker2
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Hello,
Can you please tell me if my solution is correct here:
Is x^2 < y^2 ?
1) x < y
2) -y < x
Answer I am getting is E
Original question:
Is x^2 < y^2?
i.e. Is sq. root (x^2 ) < sq. root (^2) ?
i.e. Is |x| < |y| ?
1) x < y
x = 2, y = 3 => |x| < |y|
x = -15, y = 3 => |x| not less than |y|
In-suff.
2) -y < x
=> x + y > 0
x = 2, y = 3 => |x| < |y|
x = 3, y = 2 => |x| not less than |y|
In-suff.
1 and 2:
x < y
-y < x
Adding both the above,
x - y < x + y
=> -y < y
=> -y + y < y + y
=> 0 < 2y
=> 0 < y
i.e. y > 0
We also know that x < y
Let y = 4 and x = 2 => |x| < |y|
Let y = 4 and x = -20 = > |x| is not less than |y|
Hence, answer is E
Can you please tell me if my solution is correct here:
Is x^2 < y^2 ?
1) x < y
2) -y < x
Answer I am getting is E
Original question:
Is x^2 < y^2?
i.e. Is sq. root (x^2 ) < sq. root (^2) ?
i.e. Is |x| < |y| ?
1) x < y
x = 2, y = 3 => |x| < |y|
x = -15, y = 3 => |x| not less than |y|
In-suff.
2) -y < x
=> x + y > 0
x = 2, y = 3 => |x| < |y|
x = 3, y = 2 => |x| not less than |y|
In-suff.
1 and 2:
x < y
-y < x
Adding both the above,
x - y < x + y
=> -y < y
=> -y + y < y + y
=> 0 < 2y
=> 0 < y
i.e. y > 0
We also know that x < y
Let y = 4 and x = 2 => |x| < |y|
Let y = 4 and x = -20 = > |x| is not less than |y|
Hence, answer is E













