Here stmt1 tells us that product of smallest "s" & largest "l" is +ve this can happen only if s & l have the same sign or either of them is "0", from here we cannot say about the sign of entire product as if s & l are -ve and list contains odd nos of -ve ints then product would be -ve hence NOT SUFF
stmt2 says that there are an even nos of terms , but this too is NOT SUFF as list might contain an odd nos of -ve nos but in totatily is even.
If we combine both we can say that
a) s & l have the same sign or either of them is 0
b) List contains even nos of ints
hence if both s & l are positive product of list is +ve
if both s & l are negative & list is even in size product is +ve
if either of then is "0" then nothing matters any way the product would be 0 (Whose sign I think should be taken as +ve in context of the GMAT & this problem)
SUFF
Hence answer should be "C"
Hi Hopefully,
Your interpretation is fair enough but as you mentioned
if we take a list like 2,-2,2
here smallest = -2 & largest =2 whose product is -4 negative ,this voilates the stmt 1, hence this cannot be interpreted as the list mentioned in the Q,
the idea is that if the list contains a -ve term then it must contain all negative terms in any Order or a 0 so that highest term is alos -ve thereby making their product +ve If the list contains even one +ve element this would become "l" & would voilate the stmt 1.
To sum up:
We cannot consider a list which has both -ve as well as positve terms
as s will be -ve & l would be + ve voilating the first statement.
