Tough DS from Kaplan 800.

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Tough DS from Kaplan 800.

by jo9 » Thu Dec 25, 2008 4:22 pm
At College X,the faculty-to-student ratio is 1:9.If two-thirds of the students are female and one-quarter of the faculty is female,what fraction of the combined stdents and faculty are female?

(A) 11/24
(B) 5/8
(C) 25/56
(D) 11/12
(E) It cannot be determined from the information given.

Hi guys I found this Q very tough.Jus curious to know if such tough questions are expected in the real test????
Source: — Data Sufficiency |

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by amitabhprasad » Thu Dec 25, 2008 4:35 pm
I am getting 'B"
whats OA ?
this is how I solved
pick a number for # of students = 36 LCM of 3,4,9
Thus number of faculty = 4 since ratio is 1:9
# of female student = 2/3 of 36 = 24
# of female faculty = 1/4 of 4 = 1
ratio = (24+1)/(36+4)

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by cramya » Thu Dec 25, 2008 5:48 pm
Or pick smart numbers and solve for the ratio


ratio 1:9

12 faculty

108 students

2/3*108 = 72

1/4*12 = 3

72+3/120 = 5/8

B)

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by vishubn » Thu Dec 25, 2008 5:59 pm
Fac/St =1/9

2/3*S=F
1/4 faculty is female

9,3,4 so the ideal number to plug in 36

so there are 4 faculty, and 36 students

2/3 of students is female thats is 24 female stduents

1/4 female fucaulty is 1

combined is 40 and female bothe faculty and students is 25

25/40 -- > 5/8 it is OA B

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by vishubn » Thu Dec 25, 2008 6:00 pm
Hi guys I found this Q very tough.Jus curious to know if such tough questions are expected in the real test???
I wont be surprised if u get one !!!

vishu
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by ronniecoleman » Fri Dec 26, 2008 1:02 am
Faculty = F
Student = S

S/F = 9

For Students;
Female = 2/3 S

For faculty:
Facultuy = 1/4 F

Now total females/ total people: ( 2/3S + 1/4(S/9) )/ S + S/9 ( using previous equation to convert F into S)
= 5/8

IMO B
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by thirst » Fri Dec 26, 2008 1:13 am
Questions like these can be difficult if you try to do normal math. It becomes a much easier problem when you pick numbers to attack this problem as the previous posters have demonstrated.
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by vittalgmat » Fri Dec 26, 2008 10:47 am
Here is another way.
f:s = 1: 9. So totally 1+9= 10. (here the entire problem deals with ratios; fraction is a synonym for ratio. So we can drop the x ie. we dont need to say f:s = 1x: 9x, so totally 10x)

From the q we have females are
2/3 of 9 and 1/4 of 1 ie. 18/3 + 1/4.

The q asks for ratio (or fraction) of females to combined total.

ie (18/4 + 1/4) / 10.

=> 5/8


HT Helps.

One can be almost sure to expect q of this this type on GMAT. This is a moderately tough question, probably a 600 -650 level.

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by Ian Stewart » Fri Dec 26, 2008 11:59 am
This question just asks about a weighted average, and it's just as fast, if not faster, to do with 'normal math' as it is to plug in numbers, at least if you know how to do a weighted average problem.

This is among the more common topics to see tested on the current GMAT, so if you do find this kind of question difficult, I'd strongly recommend learning how to do it and other similar questions.
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Thank u all

by jo9 » Fri Dec 26, 2008 5:53 pm
Thanks for all the response guys.

Answer is (B)