hi guys,
can the solution to this qs be as follows?
let the 5 diff numbers be n, n+1, n+2, n+3, n+4. therefore the qs asked, (n+3) + (n+4)/2 > 70?
or 2n+7>140 --> n> 66.5?
st1: n+2 = 70 or n = 68 --> SUFF
st2: mean 5n+10/5=70 --> 5n=340 --> n=68 --> SUFF
Is it wrong to use consecutive integers as an example to solve the above?
Response appreciated!
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aanchalsinha
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A certain list consists of five different integers. Is the average of the two greatest integers in the list greater than 70?
a. The median of the integers in the list is 70
for example 50 +60+ 70+(80+90)
if median is 70 then the two greatest digit will be grater that 70...
Hence can be answered.. sufficient
b. The average of the integers in the list is 70.
now if average is 70 which is 70 * 5= 350
So we can answer that the greatest two digits are greater than 70 or no.
sufficient
Hence D
a. The median of the integers in the list is 70
for example 50 +60+ 70+(80+90)
if median is 70 then the two greatest digit will be grater that 70...
Hence can be answered.. sufficient
b. The average of the integers in the list is 70.
now if average is 70 which is 70 * 5= 350
So we can answer that the greatest two digits are greater than 70 or no.
sufficient
Hence D
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