GMAT prep absolute value

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by Anurag@Gurome » Wed Mar 14, 2012 4:37 am
jkelk wrote:Hi

Please help solve the attached.

Thanks,
J
If y ≥ 0, what is the value of x?

(1) |x - 3| ≥ y ≥ 0 or we can say that |x - 3| ≥ 0
Case 1: (x - 3) ≥ 0 implies x ≥ 3
Case 2: -(x - 3) ≥ 0 implies -x + 3 ≥ 0 or x ≤ 3
No definite answer; NOT sufficient.

(2) |x - 3| ≤ -y and y ≥ 0 implies -y ≤ 0
|x - 3| ≤ 0 but |x - 3| can never be negative as |x - 3| ≥ 0
So, the only possible solution is: |x - 3| = 0 = y implies x - 3 = 0 or x = 3; SUFFICIENT.

The correct answer is B.
Anurag Mairal, Ph.D., MBA
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Gurome, Inc.
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