This question was solved already but I cant find the link
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The questions gives the costs (or information to calculate the cost) of both A and B.
The questions asks Cost of 1 Machine B compared to Cost of 2 machines A.
Cost of machine B
50000 + (50000-20%of50000)*40% = 50000+(50000-10000)*.4 = 66,000
Cost of machine A
20000 + (20000-20%of20000)*40% = 20000+(20000-4000)*.4 = 26,400
now keep in mind that we need 2 A machines
66,000 - (2*26,400) =
66,000 - 52,800 =
13,200
answers your question.
