Answer Creplayyyy wrote:In the fraction x/y, where x and y are positive integers, what is the value of y?
(1) the least common denominator of x/y and 1/3 is 6
(2) x=1
Basically, we need the least common denominator (LCD) for two fractions which is given, 6 and we have to assign the denominator for y which is factor of 6 with LCD for both fractions in mind. Within statement (1) LCD=6 we have the denominator of x/y which could be assigned as y=6
Then nominator, can not be 2, 3, or 6 it can not be 12 as well; it must be some value for us to keep the denominator y as 6. We have the statement (2) where x=1
Both statements satisfy.













