DS - ratio problem

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DS - ratio problem

by SFtraveler » Sun Jan 02, 2011 7:53 pm
DS Problem - What is most efficient way to solve this DS problem? Please provide step-by-step solution.

If the ratio of integers a, b, and c is 1:2:3, what is the value of a+b+c?

1) c-a = 8

2) b-a = 4
Source: — Data Sufficiency |

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by anshumishra » Sun Jan 02, 2011 7:59 pm
SFtraveler wrote:DS Problem - What is most efficient way to solve this DS problem? Please provide step-by-step solution.

If the ratio of integers a, b, and c is 1:2:3, what is the value of a+b+c?

1) c-a = 8

2) b-a = 4
Lets assume a=x, b = 2x, c = 3x
a+b+c = 6x = ? or x = ?

Statement 1:
c-a = 8 => 2x = 8
Sufficient

Statement 2 :
b-a = 4
=> x = 4
Sufficient

Hence D
Thanks
Anshu

(Every mistake is a lesson learned )

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by Night reader » Sun Jan 02, 2011 8:16 pm
solution of Anshu is ideal when one is familiar with ratio conversions and doesn't need to waste time on processing data.
another way to look at the problem would be
a:b:c=1:2:3 => a/c=1/3, a/b=1/2, b/c=2/3 => solving the system of equations

a/c=1/3
c-a=8 => a=4, c=12

a/b=1/2
b-a=4 => a=4, b=8

after you went through the above solution, turn to the method of Anshu and have it sunk deeper, because it's useful and less time consuming

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by SFtraveler » Mon Jan 03, 2011 9:09 pm
Thanks Anshu, that makes sense.

Night reader, thanks for your reply also. When you mention:

'solving the system of equations' then put a/c=1/3 and c-a=8 => a=4, c=12, I don't follow how a/c=1/3 turns into a=4 and c=12. Is that you just testing different sets of numbers in 1:3 ratio to get 4 and 12?

Same question for 4 and 8:
a/b=1/2
b-a=4 => a=4, b=8

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by anshumishra » Tue Jan 04, 2011 5:04 am
SFtraveler wrote:Thanks Anshu, that makes sense.

Night reader, thanks for your reply also. When you mention:

'solving the system of equations' then put a/c=1/3 and c-a=8 => a=4, c=12, I don't follow how a/c=1/3 turns into a=4 and c=12. Is that you just testing different sets of numbers in 1:3 ratio to get 4 and 12?

Same question for 4 and 8:
a/b=1/2
b-a=4 => a=4, b=8
You are welcome !
a/c = 1/3 => c = 3a
c-a = 8 => 3a-a = 8 => a=4
c = 3a = 3*4 = 12

Similarly; a/b = 1/2 => b = 2a
b-a = 4 => 2a - a = 4
=> a =4
b = 2a = 2*4 = 8.
Thanks
Anshu

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by GMATGuruNY » Tue Jan 04, 2011 7:18 am
SFtraveler wrote:DS Problem - What is most efficient way to solve this DS problem? Please provide step-by-step solution.

If the ratio of positive integers a, b, and c is 1:2:3, what is the value of a+b+c?

1) c-a = 8

2) b-a = 4
The most efficient approach is to recognize that we don't have to solve; we need only determine whether there is sufficient information to solve.

Statement 1:
c-a = 8.
Since a:b:c = 1:2:3, a/c = 1/3.
2 variables, 2 different linear equations. We can solve for a and c, then use the ratio of a:b:c to solve for b.
Sufficient.

Statement 2:
b-a =4.
Since a:b:c = 1:2:3, a/b = 1/2.
2 variables, 2 different linear equations. We can solve for a and b, then use the ratio of a:b:c to solve for c.
Sufficient.

The correct answer is D.

We should do NO math for this problem. We should recognize that since each statement gives us a second linear equation, each is sufficient to solve for all 3 variables.
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