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From 1 we can conclude thar q=0 or q= r,we have been asked if q=0,thisa cannot be answered from 1.so 1 is not sufficient.I am right.fskilnik wrote:Hi goyalsau,
My pleasure to be here!
(1) Sufficient
Please note that q^2 = qr is equivalent to q^2 - qr = 0 that is equivalent to q(q-r) = 0.
When 2 real numbers has product zero, at least one of them must be zero, therefore:
(a) q = 0 or
(b) q-r = 0, that is, q = r.
From the fact that (b) was not allowed by the question stem, we have necessarily (a), that is what we were asked, by the way.
(2) Not Sufficient
> Take r = 5 and q = 0 to answer in the affirmative ;
> Take r = 5 and q = 1 to answer in the negative.
We are done.
Regards,
Fábio.
Important: DO NOT CANCEL common factors, put them into "evidence" (then you do not fall into the trap of sttm (1)!!
No, you are not. Please be more humble and read the question stem and (for instance) my answer more carefully.novel wrote:From 1 we can conclude thar q=0 or q= r,we have been asked if q=0,thisa cannot be answered from 1.so 1 is not sufficient.I am right.
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