If the operation o is defined for all positive integers x and w by x o w = 2^x/2^w, then (3o1)o 3 =
a) 2
b) 4
c) 8
d) 16
e) 32
a) 2
b) 4
c) 8
d) 16
e) 32
we need to solve the one in parenthesis firstgmat_junior wrote:If the operation o is defined for all positive integers x and w by x o w = 2^x/2^w, then (3o1)o 3 =
a) 2
b) 4
c) 8
d) 16
e) 32
3o1 = 2^3/2^1= 8/2 = 4
now (3o1)o 3 can be re written as 4o3
2^4/2^3 = 2
hope that helps..
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