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by crimson2283 » Sun Feb 27, 2011 9:24 am
The price of T.V set is increased by 40 % of the cost price and then decreased by 25% of the new price . On
selling, the profit for the dealer was Rs.1,000 . At what price was the T.V sold?
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by Night reader » Sun Feb 27, 2011 9:47 am
given: CP-cost price, P-price, I-profit, find P-?
solution: P=CP*(1.4)*(0.75); P-CP=1,000;
P=1,000+CP; P=(14/10)*(3/4)*CP --> 42CP/40=1,000+CP, 42CP=40,000+40CP, CP=20,000, P=20,000+1,000=21,000
crimson2283 wrote:The price of T.V set is increased by 40 % of the cost price and then decreased by 25% of the new price . On selling, the profit for the dealer was Rs.1,000 . At what price was the T.V sold?
My knowledge frontiers came to evolve the GMATPill's methods - the credited study means to boost the Verbal competence. I really like their videos, especially for RC, CR and SC. You do check their study methods at https://www.gmatpill.com
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by maihuna » Sun Feb 27, 2011 9:59 am
Assuming 100 as CP, sell price = 140*75/100 = 420/4 = 105
So Profit % = 05
Since 5% => 1000 => SP = 105% = 105*1000/5 = 21000
crimson2283 wrote:The price of T.V set is increased by 40 % of the cost price and then decreased by 25% of the new price . On
selling, the profit for the dealer was Rs.1,000 . At what price was the T.V sold?
Charged up again to beat the beast :)
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by tomato1 » Sun Feb 27, 2011 11:41 am
When something is changed by x% & changed by y%.
The net change is given by,
[+/-]X [+/-]y [+/-]XY/100
+ for increase
- for decrease

=X-Y-XY/100
=40-15-(40*25)/100
=5%

5% of CP=100
So, CP=20000
SP=CP+1000=21000
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