tough question

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Re: tough question

by logitech » Thu Jan 08, 2009 2:33 pm
(1) 3|x2 – 4| = y – 2

This first statement tells us that the left side of the equation is a non-negative number. We do not have X in the rest of the question so

y-2>0

(2) |3 – y| = 11

a) 3-y = 11 , this gives a negative y

b) y-3 -11 , this gives us a positive y

Since we know y can not be negative, we can choose (C)
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by ronniecoleman » Fri Jan 09, 2009 12:24 am
What is the value of y?

(1) 3|x2 – 4| = y – 2

(2) |3 – y| = 11


from 2)

y = -8

y = 14


insuff

from 1)

no idea about the value of y but know its sign

insuff


from 1) & 2)

we know y has to be positive for first equation

Go with C
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