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by chaitanya.mehrotra » Sun Jul 24, 2011 12:22 pm
In the figure to the right, if point C is the center of the circle and DB = 7, what is the length of DE in triangle EDB?

(1) x = 60°

(2) DE || CA


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OA after some discussion
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Source: — Data Sufficiency |
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by clock60 » Sun Jul 24, 2011 12:44 pm
B for me, if DE||CA, then triangles DEB and CAB are similar, so DE is also 7.
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by ColumbiaVC » Sun Jul 24, 2011 8:29 pm
C
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by Ozlemg » Mon Jul 25, 2011 12:23 am
IMO D.

Statement 1 helps us to figure out that AC // DE. So we can solve the prolem.

Statement 2 is also sufficient. (Property of similarity in triangles)

Thanks
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by clock60 » Mon Jul 25, 2011 8:52 am
Ozlemg wrote:IMO D.

Statement 1 helps us to figure out that AC // DE. So we can solve the prolem.

Statement 2 is also sufficient. (Property of similarity in triangles)

Thanks
hi Ozlemg
can you elaborate how you established that AC||DE using st 1?i am a bit confused
thanks
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by edge » Mon Jul 25, 2011 6:12 pm
Ozlemg wrote:IMO D.

Statement 1 helps us to figure out that AC // DE. So we can solve the prolem.
It doesn't. Yes, internal angles of triangle ABC are 60° each, but try to visualize 'E' as just beyond 'A' on BA. It doesn't violate Statement 1, and DE != 7.

The correct answer is B.
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by sandeep1306 » Mon Jul 25, 2011 10:55 pm
Indeed the correct answer is B
in order to determine the length of DE, the only way is to figure out whether DE is parallel AC.
option 1 doesnt reveal this.
option 2 gives us the answer.

just for info , if DE//AC and AB:AD =m:n
Then,

AC = m/(m+n) DE
Thanks,
Sandeep
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