Challenging Problem

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Stockmoose16: Master | Next Rank: 500 Posts; Posts: 347; Joined: Mon Aug 04, 2008 1:42 pm; Thanked: 1 times

by Stockmoose16 » Wed Aug 20, 2008 4:58 pm

If w,x,y,z are integers where w<x<y<z and wxyz=k, then what is the value of w+z if K=770?

Can anyone solve this with an explanation?

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Source: Beat The GMAT — Problem Solving | Wed Aug 20, 2008 4:58 pm

nervesofsteel: Legendary Member; Posts: 594; Joined: Thu Aug 14, 2008 11:51 pm; Thanked: 12 times

by nervesofsteel » Wed Aug 20, 2008 5:06 pm

There is no definite answer for this question

As 2*5*7*11 = 770
also -2*(-5)*(-7)*(-11) = 770

in both cases value of w+z is different

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parallel_chase: Legendary Member; Posts: 1153; Joined: Wed Jun 20, 2007 6:21 amFollowed by: 2 members; Thanked: 146 times

by parallel_chase » Wed Aug 20, 2008 5:13 pm

770 = 2*5*7*11

prime factorize 770 and you'll get the exact above.

770=wxyz

we know that

w<x<y<z
2<5<7<11

Hence w+z = 2+11 = 13

Hope this helps.

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