Hmm, from (2), we know x < |x| i.e. x < 0. Why is (2) alone not sufficient ?dunkin77 wrote:x>0?
(1)|x|>x^2
(2)x<|x^1|
Yeah, 1 tells us 0<x<1 (or) -1<x<0. insufficient.
Hmm, from (2), we know x < |x| i.e. x < 0. Why is (2) alone not sufficient ?dunkin77 wrote:x>0?
(1)|x|>x^2
(2)x<|x^1|