kwah wrote:Attached is a question from GMAT Prep Test #2.
What is the most efficient way of achieving the result?
Answer: E
Thanks,
K
It is given that each dessert platter contains an equal number of cheese and fruit. So, the possible combinations are:
(1)
2 kinds of cheese and 2 kinds of fruits
Number of ways of choosing 2 kinds of cheese and 2 kinds of fruits = 6C2 * 2C2 = 6!/(2! * 4!) * 2!/2! = (6 * 5)/2 =
15
(2)
1 kind of cheese and 1 kind of fruit
Number of ways of choosing 1 kind of cheese and 1 kind of fruits = 6C1 * 2C1 = 6 * 2 =
12
Therefore, number of different dessert platters that the restaurant can offer = 15 + 12 =
27
The correct answer is
E.
