Problem 6:
n= Square root (2/7+1/3+4/9+2/3+5/9+5/7+x)
In the equation above, if n is an integer, which of the following could be a possible value of x?
Indicate all such values:
A) 0
B) 2/63
C) 1
D) 65/63
E) 4
the way I solved it was reorder the fractions as follows
n = Square root ((1/3+2/3)+(3/7+5/7)+(4/9+5/9)+x) =
n = Square root (1+1+1+x)
n = Square root (3+x)
But the problem for me is i do not know what to do next? to answer the chooses.
[/list]
n= Square root (2/7+1/3+4/9+2/3+5/9+5/7+x)
In the equation above, if n is an integer, which of the following could be a possible value of x?
Indicate all such values:
A) 0
B) 2/63
C) 1
D) 65/63
E) 4
the way I solved it was reorder the fractions as follows
n = Square root ((1/3+2/3)+(3/7+5/7)+(4/9+5/9)+x) =
n = Square root (1+1+1+x)
n = Square root (3+x)
But the problem for me is i do not know what to do next? to answer the chooses.
[/list]
Last edited by phoenix9801 on Mon May 07, 2012 2:32 pm, edited 1 time in total.

















