GMAT Prep 1 #3_DS Word Prob #29

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by Mike@Magoosh » Mon Mar 19, 2012 4:16 pm
Hi, there. I'm happy to help with this. :)

Jason's salary and Karen's salary were each p percent greater in 1998 than in 1995. What is the value of p?
(1) In 1995 Karen's salary was $2000 greater than Jason's.
(2) In 1998 Karen's salary was $2240 greater than Jason's.


Statement #1: In 1995 Karen's salary was $2000 greater than Jason's.
Let K be Karen's salary in 1995, and J, Jason's salary in 1995. This tell us

K - J = 2000

Absolutely no information about p. This statement, by itself, is wildly insufficient.

Statement #1: In 1998 Karen's salary was $2240 greater than Jason's.

Here, p is an integer percent --- change it into a multiplier: M = (1 + p/100). Then

M*K - M*J = M*(K - J) = 2440.

Here, with this statement only, we have no information about J - K, so we can't solve for M, which would allow us to solve for p. Statement #2, by itself, is insufficient.

Combined statements:
We have
(i) K - J = 2000
(ii) M*(K - J) = 2440

Combining, we have M*2000 = 2440 ---> M = 2440/2000 = 1.22
M = 1 + p/100 = 1.22
p/100 = 0.22
p = 22%

Combining the statements allows us to solve for the percent. The moral is: the difference between two quantities increases by the same percent by which the individual quantities increase. Combined, the statements are sufficient.

Answer = C

Does all this make sense? Let me know if you have any further questions.

Mike :)
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by Anurag@Gurome » Mon Mar 19, 2012 7:39 pm
kwah wrote:I have attached a question from GMAT Prep Test 1.

What is the most efficient way to achieve this result?

Answer:C

Please advise, thank you.
K
Let Jason's and Karen's salary in 1995 be Jx and Kx respectively, and
Jason's and Karen's salary in 1998 be Jy and Ky respectively.

Given: Jy = Jx(1 + p/100) and Ky = Kx(1 + p/100)

(1) Kx = 2000 + Jx but we cannot find the value of p from this info; NOT sufficient.

(2) Ky = 2440 + Jy but we cannot find the value of p from this info; NOT sufficient.

Combining (1) and (2),
Ky = 2440 + Jy
Kx(1 + p/100) = 2440 + Jx(1 + p/100)
Kx(1 + p/100) - Jx(1 + p/100) = 2440
(1 + p/100)[Kx - Jx) = 2440 ... Equation (A)
From statement 1, we know Kx = 2000 + Jx or Kx - Jx = 2000
Plugging the value of Kx - Jx in Equation (A),
(1 + p/100)2000 = 2440, solving which we can easily find the value of p; SUFFICIENT.

The correct answer is C.
Anurag Mairal, Ph.D., MBA
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