1) a < b
let a = 2 and b = 3
f(a) = 2-4 = -2
f(b) = 3-9 = -6
Therefore f(a) > f(b)
let a = -2 and b = 3
f(a) = -2(4) = -8
f(b) = 3-9 = -6
Therefore f(a) < f(b)
INSUFF
2) a^2< b^2
We can always take a positive root of a and negative root of b and vice-versa, so 2 will never be SUFF
Both statements together also dont make any difference.
Ans E.
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