mmslf75 wrote:Is the product 2*X*5*Y an even integer ?
1) 2 + x + 5 + y is an even integer
2) x - y is an odd integer
Answer :: C
Source :: GMATCL
IMO B
Any clue why B is rejected ??
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pandeyvineet24
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Are you sure you got the question right ?. Question stem has 2*X*5*Y, so the product will always be even.
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rohan_vus
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Not sure abt the question
But if the question is what it is , then i see X and Y are not mentioned as integers..and answer must be C then
In that case B cant be the answer coz consider X = 1.5 and Y = .5 ( considering any number coz its not mentioned they are integer) then X - Y = 1. which is an odd integer but your expression 2*X*5*Y is not an even integer
But 2*X*5*Y will surely be an an even integer if we can prove X*Y is an integer..
If you take A alone then we see x + Y is an odd integer if X is 1.3 and y is 1.7...so A alone not sufficient
Combining both A and B you can see X - Y = odd integer and X + Y = odd integer then X and Y are definitely integers...But y so , simple reason , use stmnts from A and B ==> ( X + Y) + ( X - Y) = odd + odd = even ==> 2X = even then X got to be an integer ...it X is an integer then Y has to be an integer...
But if the question is what it is , then i see X and Y are not mentioned as integers..and answer must be C then
In that case B cant be the answer coz consider X = 1.5 and Y = .5 ( considering any number coz its not mentioned they are integer) then X - Y = 1. which is an odd integer but your expression 2*X*5*Y is not an even integer
But 2*X*5*Y will surely be an an even integer if we can prove X*Y is an integer..
If you take A alone then we see x + Y is an odd integer if X is 1.3 and y is 1.7...so A alone not sufficient
Combining both A and B you can see X - Y = odd integer and X + Y = odd integer then X and Y are definitely integers...But y so , simple reason , use stmnts from A and B ==> ( X + Y) + ( X - Y) = odd + odd = even ==> 2X = even then X got to be an integer ...it X is an integer then Y has to be an integer...
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mehravikas
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Why not 'E'?
X = 0, Y = 1or X = 1, Y = 0 would still given the desired result but depending on X and Y the product could be even or odd.
X = 0, Y = 1or X = 1, Y = 0 would still given the desired result but depending on X and Y the product could be even or odd.
rohan_vus wrote:Not sure abt the question
But if the question is what it is , then i see X and Y are not mentioned as integers..and answer must be C then
In that case B cant be the answer coz consider X = 1.5 and Y = .5 ( considering any number coz its not mentioned they are integer) then X - Y = 1. which is an odd integer but your expression 2*X*5*Y is not an even integer
But 2*X*5*Y will surely be an an even integer if we can prove X*Y is an integer..
If you take A alone then we see x + Y is an odd integer if X is 1.3 and y is 1.7...so A alone not sufficient
Combining both A and B you can see X - Y = odd integer and X + Y = odd integer then X and Y are definitely integers...But y so , simple reason , use stmnts from A and B ==> ( X + Y) + ( X - Y) = odd + odd = even ==> 2X = even then X got to be an integer ...it X is an integer then Y has to be an integer...
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mmslf75
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pandeyvineet24 wrote:Are you sure you got the question right ?. Question stem has 2*X*5*Y, so the product will always be even.
mmslf75 wrote:Is the product 2*X*5*Y an even integer ?
1) 2 + x + 5 + y is an even integer
2) x - y is an odd integer
Answer :: C
Source :: GMATCL
IMO B
Any clue why B is rejected ??
The question is right, but not traditional. That's why I have posted here ...
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Testluv
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Vikas,mehravikas wrote:Why not 'E'?
X = 0, Y = 1or X = 1, Y = 0 would still given the desired result but depending on X and Y the product could be even or odd.
rohan_vus wrote:Not sure abt the question
But if the question is what it is , then i see X and Y are not mentioned as integers..and answer must be C then
In that case B cant be the answer coz consider X = 1.5 and Y = .5 ( considering any number coz its not mentioned they are integer) then X - Y = 1. which is an odd integer but your expression 2*X*5*Y is not an even integer
But 2*X*5*Y will surely be an an even integer if we can prove X*Y is an integer..
If you take A alone then we see x + Y is an odd integer if X is 1.3 and y is 1.7...so A alone not sufficient
Combining both A and B you can see X - Y = odd integer and X + Y = odd integer then X and Y are definitely integers...But y so , simple reason , use stmnts from A and B ==> ( X + Y) + ( X - Y) = odd + odd = even ==> 2X = even then X got to be an integer ...it X is an integer then Y has to be an integer...
if either of x or y were zero, then the product of the expression in the question stem would be zero, and zero is an even integer.
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mehravikas
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God how could I forget that 
Testluv wrote:Vikas,mehravikas wrote:Why not 'E'?
X = 0, Y = 1or X = 1, Y = 0 would still given the desired result but depending on X and Y the product could be even or odd.
rohan_vus wrote:Not sure abt the question
But if the question is what it is , then i see X and Y are not mentioned as integers..and answer must be C then
In that case B cant be the answer coz consider X = 1.5 and Y = .5 ( considering any number coz its not mentioned they are integer) then X - Y = 1. which is an odd integer but your expression 2*X*5*Y is not an even integer
But 2*X*5*Y will surely be an an even integer if we can prove X*Y is an integer..
If you take A alone then we see x + Y is an odd integer if X is 1.3 and y is 1.7...so A alone not sufficient
Combining both A and B you can see X - Y = odd integer and X + Y = odd integer then X and Y are definitely integers...But y so , simple reason , use stmnts from A and B ==> ( X + Y) + ( X - Y) = odd + odd = even ==> 2X = even then X got to be an integer ...it X is an integer then Y has to be an integer...
if either of x or y were zero, then the product of the expression in the question stem would be zero, and zero is an even integer.












