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by jayhawk2001 » Sun Apr 15, 2007 3:23 pm
5^21 X 4^11 = 2X10^n what is n?

5 * 5^20 * 4 * 4^10 = 2* 10^n
20 * 5^20 * 2^20 = 20 * 10^(n-1)
20 * 10^20 = 20 * 10^(n-1)

n-1 = 20
n = 21
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by djsir007 » Sun Apr 15, 2007 3:40 pm
is 4^10 = 2^20

is this the only set of numbers that you can swap like this?

Thank you for the help?
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by jayhawk2001 » Sun Apr 15, 2007 5:07 pm
djsir007 wrote:is 4^10 = 2^20

is this the only set of numbers that you can swap like this?

Thank you for the help?
Rule of thumb is (x^y)^z = x^(y*z)

So, 4^10 = (2^2)^10 = 2^20
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by Cybermusings » Mon Apr 16, 2007 3:12 am
dude this has been posted in an old thread...please check the old posts before posting new ones, since the questions criculating become repititive
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by ns88 » Sat May 12, 2007 10:35 am
5^21 (4^11) =2 (10^n)

let's work with 2 (10^n)

2 (5^n) (2^n)

5^n (2^n+1)

5^n (4^((n+1)/2)

n=21
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