BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem
TTP OnDemand GMAT Video Course
Featured Course

Target Test Prep GMAT OnDemand

Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.

  • 715+ score guarantee — highest in the industry (99th percentile)
  • 52 chapters · 1,500+ lessons · 4,000+ practice questions
  • 400 hours of video · 1,500+ instructor-led HD smartboard lessons
  • 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
  • 24/7 live support + weekly Zoom office hours with GMAT instructors
  • TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
  • 1,200+ flashcards + AI-powered study assistant & daily calendar
  • OnDemand, LiveTeach & GMAT Bootcamp formats available
  • Also: GRE, SAT Math & Executive Assessment courses
  • MBA Admissions Consulting now available
  • 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
  • 200,000+ students served
  • 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★ 5.0 (559 reviews)
130-pt guarantee
$0 to start then $127/mo
Start Free 5-Day Trial Read 559 Reviews →

GMATPrep Q

Problem Solving — algebra and arithmetic (GMAT Focus Edition)
Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Source: — Quantitative Reasoning |
Legendary Member
Posts: 829
Joined: Mon Jul 07, 2008 10:09 pmFollowed by: 3 members
Location: INDIA
Thanked: 84 times

Re: GMATPrep Q

by sudhir3127 » Sat Aug 23, 2008 9:47 pm
smehmood wrote:What is the solution to the attached problems?
Thanks
M
its C

plug in the values and it will be cake walk...

Assume X=2 and Y =2

1. sqrt ( x+y)/2x
sqrt (4)/4 = 2/4 = 1/2........................................1

2. (rt x+ rt y)/x+y
(rt2 + rt 2)/4
2rt2/4 = rt2/2 > 1/2...................................................2


3. (sqrtx - rt y)/x+y = 0....................................3

hence C

.Hope it helps..
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Junior | Next Rank: 30 Posts
Posts: 29
Joined: Fri Jul 04, 2008 6:57 pm
Thanked: 1 times

by kv_ajay » Sun Aug 24, 2008 12:02 am
Sudhir,

You got the correct answer but i think there are various opportunities to plug in numbers and too much work.

Explanation from my point would be
Root (X) + Root (Y) => Root (X+Y)
e.g. X= 4, Y = 16 then 2+4 > 4.47

so Root (X) + Root (Y)
---------------------
Root (X+Y) Root (X+Y)

So 1/Root(X+Y) is multiplied by integer > 1 so it will always be greater than 1/(Root X+Y)
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Senior | Next Rank: 100 Posts
Posts: 54
Joined: Sat May 10, 2008 1:48 pm

by smehmood » Sun Aug 24, 2008 8:15 am
So, should we plug-in numbers in these type of questions?
I plug in numbers and I was getting both I and II greater then the number in question.

Ajay, you did not explain how you will compare x+y (denominator is II) with 2x (denominator in I)?

Thanks
M
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Junior | Next Rank: 30 Posts
Posts: 25
Joined: Tue Jul 01, 2008 11:54 am
Location: San Diego

by somail » Tue Aug 26, 2008 12:28 pm
Plugging numbers in is okay, but you need to be carefull. The question says "must be greater than" meaning in all situations.

Lets say we pick x=4 and y=12

for I we get:

sqrt(16)/8 = 1/2 which is greater

but if we were to use x=12 and y=4 we get:

sqrt(16)/24 = 1/6 which is less.

So in this situation you can pick numbers, but just be extra careful to think about all possibilities.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1