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Cramya and his taste of fashion ;-)

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by logitech » Tue Nov 25, 2008 10:52 pm
On Tuesday, Cramya purchases exactly 3 new shirts, 2 new sweaters, and 4 new hats, On the following day and each subsequent day thereafter, Cramya wears one of his new shirts together with one of his new sweaters and one of his new hats. Cramya avoids wearing the exact same combination of shirt, sweater, and hat for as long as possible. On which day is this no longer possible?

OA Saturday
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by jimmiejaz » Wed Nov 26, 2008 1:32 am
Cramya buys all the clothes on tuesday. And he starts wearing them on wednesday.
total no of combinations 4*3*2 = 24
Counting 22 days from wednesday, we will get wednesday. Adding 2 more days. So, on Friday he will wear last of his combinations and by Saturday it will no longer be possible.

Nice question though. :wink:
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by mals24 » Wed Nov 26, 2008 4:31 am
Yup agree with jimmiejaz

Total combinations = 24

So Cramya can wear a new combination in 24 days. On the 25th day cramya will be out of combinations and will have to start all over again.

He starts on Wednesday, Wednesday - Tuesday is 1 week

24 days is 3 weeks and 3 days

3 weeks end on a Tuesday + 3 days = Friday

So cramya will run out off combinations on Saturday.
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