If xy > 0 , does (x-1)(y-1) = 1 ?
1. x+y = xy
2. x=y
OA = A
I got it as D and I can explain why. Don't know if I am doing some stupid mistake.
1 . Is sufficient pretty straightforward.
2. (y-1)(y-1)=1 thus y^2 - 2y=0 thus we get either y=0 or y=2. since they have mentioned xy>0 y can't be zero, it has to be 2 and hence x=2 and I am getting Sufficient answer. If the OA in OG is correct then I am really doing some real stupid mistake.
Can someone point out what mistake I am doing?
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1. x+y = xy
2. x=y
OA = A
I got it as D and I can explain why. Don't know if I am doing some stupid mistake.
1 . Is sufficient pretty straightforward.
2. (y-1)(y-1)=1 thus y^2 - 2y=0 thus we get either y=0 or y=2. since they have mentioned xy>0 y can't be zero, it has to be 2 and hence x=2 and I am getting Sufficient answer. If the OA in OG is correct then I am really doing some real stupid mistake.
Can someone point out what mistake I am doing?
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