98 = (2)(7)(7) = (2^1)(7^2)VJesus12 wrote:What is the largest value of integer n such that 98^98 is divisible by 7^n?
A. 98
B. 105
C. 148
D. 164
E. 196
[spoiler]OA=E[/spoiler]
Source: GMAT Club Tests
So, 98^98 = [(2^1)(7^2)]^98
= (2^98)(7^196)
What is the largest value of integer n such that 98^98 is divisible by 7^n?
Since 98^98 = (2^98)(7^196), the largest value of n is 196
Answer: E
Cheers,
Brent
