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Anna has to visit at least 2 European cities on her vacation

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by AAPL » Tue Feb 19, 2019 4:57 am

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Veritas Prep

Anna has to visit at least 2 European cities on her vacation trip. If she can visit only London, Paris, Rome, or Madrid, how many different itineraries, defined as the sequence of visited cities, can Anna create?

A. 12
B. 36
C. 48
D. 60
E. 72

OA D
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by Brent@GMATPrepNow » Tue Feb 19, 2019 6:02 am
AAPL wrote:Veritas Prep

Anna has to visit at least 2 European cities on her vacation trip. If she can visit only London, Paris, Rome, or Madrid, how many different itineraries, defined as the sequence of visited cities, can Anna create?

A. 12
B. 36
C. 48
D. 60
E. 72

OA D
We need to consider 3 different cases:
i) Anna visits 2 cities
ii) Anna visits 3 cities
iii) Anna visits 4 cities

i) Anna visits 2 cities
There are 4 options for the FIRST city and 3 options for the SECOND city
So, the total number of 2-city itineraries = (4)(3) = 12

ii) Anna visits 3 cities
There are 4 options for the FIRST city, 3 options for the SECOND city, and 2 options for the THIRD city
So, the total number of 3-city itineraries = (4)(3)(2) = 24

ii) Anna visits 4 cities
There are 4 options for the FIRST city, 3 options for the SECOND city, 2 options for the THIRD city, and 1 option for the FOURTH city
So, the total number of 4-city itineraries = (4)(3)(2)(1) = 24

TOTAL number of itineraries 12 + 24 + 24 = 60

Answer: D

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by Scott@TargetTestPrep » Thu Feb 21, 2019 4:52 pm
AAPL wrote:Veritas Prep

Anna has to visit at least 2 European cities on her vacation trip. If she can visit only London, Paris, Rome, or Madrid, how many different itineraries, defined as the sequence of visited cities, can Anna create?

A. 12
B. 36
C. 48
D. 60
E. 72

OA D
To visit at least 2 of the 4 given European cities is to visit 2, 3, or all 4 cities. Since each itinerary must be made up of a different sequence of cities, order is important, and thus we have a permutation problem. The permutation formula is nPr = n! / (n - r)!. Let's determine the number of ways she can visit 2, 3, or all 4 cities.

The number of ways she can visit exactly 2 cities is 4P2 = 4! / 2! = 4 x 3 = 12.
The number of ways she can visit exactly 3 cities is 4P3 = 4! / 1! = 4 x 3 x 2 = 24.
The number of ways she can visit all 4 cities is 4P4 = 4! / 0! = 4 x 3 x 2 x 1 = 24. (Recall that 0! = 1.)

Thus, the total number of ways she can visit at least 2 of the 4 cities is 12 + 24 + 24 = 60.

Answer: D

Scott Woodbury-Stewart
Founder and CEO
[email protected]

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