true EXCEPT

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true EXCEPT

by sanju09 » Thu Apr 16, 2009 3:09 am
x is the sum of y consecutive integers. w is the sum of z consecutive integers. If y = 2 z, and y and z are both positive integers, then each of the following could be true EXCEPT
A. x = w
B. x > w
C. x/y is an integer
D. w/z is an integer
E. x/z is an integer



OA C
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by scoobydooby » Thu Apr 16, 2009 4:21 am
am getting all could be true. what am i missing?

1) x=w
say w=(0+1+2)=3 and x=(-2-1+0+1+2+3)=3. could be true.

2) x>w
say w=(-1+0+1)=0 and x= (1+2+3+4+5+6) could be true.

3) x/y integer.
say x=(-1+0+1)=0, y=3 0/3=0 which is an integer. could be true.

4) w/z integer
say w=(-1+0+1)=0, z=3; 0/3=0 an integer. could be true

5) x/z is an inetger.
say x= (-2-1+0+1+2)=0, z=2
x/z=0/2=0 an integer. could be true.
Last edited by scoobydooby on Thu Apr 16, 2009 4:26 am, edited 1 time in total.

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by sanju09 » Thu Apr 16, 2009 4:25 am
scoobydooby wrote:am getting all could be true. what am i missing?

1) x=w
say w=(1+2)=3 and x=(-2-1+0+1+2+3)=3. could be true.

2) x>w
say w=(-1+0+1)=0 and x= (1+2+3+4+5+6) could be true.

3) x/y integer.
say x=(-1+0+1)=0, y=3 0/3=0 which is an integer. could be true.

4) w/z integer
say w=(-1+0+1)=0, z=3; 0/3=0 an integer. could be true

5) x/z is an inetger.
say x= (-2-1+0+1+2)=0, z=2
x/z=0/2=0 an integer. could be true.
You are missing that y is even only :wink:
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by scoobydooby » Thu Apr 16, 2009 4:37 am
oops!, thanks sanju09

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by Mr2Bits » Thu Apr 16, 2009 6:09 am
Removed due to Sanju09 thinking he is better than everyone.
sanju09 wrote:
sjd00d wrote:D. 25% in my opinion. Let the sides be 1 before cut, after the cut 1 side not painted but 1/2+1/2+1/2+1/2+1 painted, 1/4 = 25%
:oops: This is really very pathetic elucidation to the problem.
Image
Last edited by Mr2Bits on Thu Apr 16, 2009 6:48 am, edited 1 time in total.

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by sanju09 » Thu Apr 16, 2009 6:21 am
Mr2Bits wrote:Just plug in Numbers.

Y = 1, 2, 3
X=6

Z = 1, 2, 3, 4, 5, 6
W = 21

A. x = w - False
B. x > w - false
C. x/y is an integer - True 6/3 = 2
Test with another set to be sure
4,5,6 = y 15= x
15/3 = True

D. w/z is an integer - 21/6 - False
E. x/z is an integer - 6/6 true Try a second set
4,5,6 = 15 = X
15/6 = False

C is the only one that will always be true
But we are looking for a choice that can never be true; did you read the question with care? Your end-line only suggests that C is not an answer to the question, which contradicts the OA. You have probably ignored so many mathematical concepts and a few directives supplied in the question. Need to work hard, really!! B-)
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by Mr2Bits » Thu Apr 16, 2009 6:38 am
sanju09 wrote: But we are looking for a choice that can never be true; did you read the question with care? Your end-line only suggests that C is not an answer to the question, which contradicts the OA. You have probably ignored so many mathematical concepts and a few directives supplied in the question. Need to work hard, really!! B-)
You really need to work hard on not being such a condescending a-hole. Your underlying tone is uncalled for and not welcome here. If you want to talk to someone like your better than they are you wont go far in life. People do mis-read and take different approaches to problems. I misread the problem, so what it’s early and I was up late last night. Your mockery is unnecessary.

Here is a better approach so I don't have to hear your comments anymore.

Well since we can determine that y will always be even.

Let's say there are 2 integers.

x = 5+6 = 11

11/2 is not an integer

let's say there are 4 integers.

x = 1+2+3+4 = 10

10/4 is not an integer

let's say there are 6 integers.

x=1+2+3+4+5+6 = 21

21/6 is not an integer.

This always holds true.

I believe that the sum of an even number of consecutive integers will never be a multiple of the number of integers.

x/y will never be an integer.

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by sanju09 » Thu Apr 16, 2009 11:25 pm
True! The sum of an even number of consecutive integers is never divisible by the number of integers, whereas the sum of an odd number of consecutive integers is always divisible by the number of integers.

Where and how did you feel that I was trying to pull your leg, Mr2bits? I simply did what is my duty; and the example post of mine displayed by you above is an incomplete show of the entire sequel; I'm thankful to Mr Ian Stuart who guided me right after that post and I did never repeat demoralising words since then. Though I didn't get most of the Grammar and vocabulary used by you in your above post, but I can still feel the heat it tried to propagate. I did never claim that I am the best, it is same as saying that I am the greatest fool; why should I say or suggest that, Mr2bits. In the end, I would request Mr Ian Stuart to see into the matter and one more time, guide me please, about what was wrong in my comments after your answer. B-)
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by 4seasoncentre » Thu Apr 16, 2009 11:57 pm
sanju09 wrote:
But we are looking for a choice that can never be true; did you read the question with care? Your end-line only suggests that C is not an answer to the question, which contradicts the OA. You have probably ignored so many mathematical concepts and a few directives supplied in the question. Need to work hard, really!! B-)
I am confused. You post a question you already know the answer to, and then chastise a colleague who tries to help?

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by sanju09 » Fri Apr 17, 2009 12:03 am
4seasoncentre wrote:
sanju09 wrote:
But we are looking for a choice that can never be true; did you read the question with care? Your end-line only suggests that C is not an answer to the question, which contradicts the OA. You have probably ignored so many mathematical concepts and a few directives supplied in the question. Need to work hard, really!! B-)
I am confused. You post a question you already know the answer to, and then chastise a colleague who tries to help?
I wish all of us should focus on to the cause what we are here for :)
The mind is everything. What you think you become. -Lord Buddha



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