BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

math question

Expert replies
by dzelkas » Sun May 25, 2008 11:46 am
Can someone pls help me understand this
X and Y are consecutive positive integers and:
x>0
X^2-1>y^2-4y+x-1

a) y = or > than 0
b) y > 0
c) y > 1
d) y > 7
e) y > 8
Which of the following represents all the possible values of y?

correct answer is B) It explains as follows by factoring out

x^2-1>y^2-4y+x-1
x^2-x>y^2-4y
x(x-1)>y(y-4)
(y+1)(y+1-1)>y(y-4)
y+1>y-4
1>4 (shouldn't that be 1>-4???)

solution explains:
When we divided both parts of the equation by Y , we assumed that it is greater than 0. Since at the end we are left without a variable, this means that the equation works for any value where
Now any integers greater than y> 3/2 are part of the solution to enequality.

Can someone please explain?
Join the discussion
Source: — Problem Solving |

by VP_Tatiana » Mon May 26, 2008 8:20 pm
Hi there,

I agree the explanation with elimiting the variable from the equation by making an assumption is very roundabout. Let me try explaning another way.

From the algebra you showed, we can reduce the eq to:

x(x-1) > y(y-4)

Now, let's go through the answer choices to find out which values of y satisfy the equation.


Starting with answer choice A, suppose y = 0. Then, x(x-1) > 0. Since our only restriction on x is that x > 0, it is perfectly valid to pick x = 1. However, in that case we get 0 > 0. Since that is not true, y = 0 does not satisfy this equation.

Moving on to asnwer choice B, let's say y > 0. Since y is an integer, this is equivalent to y >= 1. Thus, we get:

x(x-1) > y(y -4) >= -3.

Is it always true that x(x-1) >= -3?

Well, x > 0. Again, since it is an integer this means x >= 1. The smallest value of x(x-1) is thus 1(1-1) = 0.

So, when y > 0, we get 0 > -3. Since that is true, y > 0 satisfies the equation and our answer is B.

Hope this explanation made more sense,

Tatiana
Tatiana Becker | GMAT Instructor | Veritas Prep
Join the discussion

by netigen » Mon May 26, 2008 8:57 pm
Whats the source of this question, it doesn't look like much thought was put in while writing it:

it provides redundant information

1. X and Y are consecutive positive integers
2. x>0

then in the answers it provides option that are obviously contradicting the info in the stem

(a) y = or > than 0
Join the discussion