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by sanju09 » Fri Feb 19, 2010 4:19 am
Marcus can spend no more than $120 on jeans and shirts for school. He buys 3 pairs of jeans at $32 each. If x represents the dollar amount he can spend on shirts, which of the following inequalities could be used to determine the possible values for x?
(A) (3) × 32 - x ≤ 120
(B) (3) × 32 - x ≥ 120
(C) (3) × 32 + x ≤ 120
(D) (3) × 32 + x ≥ 120
(E) x ≤ (3) × 32
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by ajith » Fri Feb 19, 2010 4:34 am
sanju09 wrote:Marcus can spend no more than $120 on jeans and shirts for school. He buys 3 pairs of jeans at $32 each. If x represents the dollar amount he can spend on shirts, which of the following inequalities could be used to determine the possible values for x?
(A) (3) × 32 - x ≤ 120
(B) (3) × 32 - x ≥ 120
(C) (3) × 32 + x ≤ 120
(D) (3) × 32 + x ≥ 120
(E) x ≤ (3) × 32
[spoiler]3*32+x≤ 120

C[/spoiler]
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by harsh.champ » Fri Feb 19, 2010 5:08 am
sanju09 wrote:Marcus can spend no more than $120 on jeans and shirts for school. He buys 3 pairs of jeans at $32 each. If x represents the dollar amount he can spend on shirts, which of the following inequalities could be used to determine the possible values for x?
(A) (3) × 32 - x ≤ 120
(B) (3) × 32 - x ≥ 120
(C) (3) × 32 + x ≤ 120
(D) (3) × 32 + x ≥ 120
(E) x ≤ (3) × 32
Marcus can spend no more than $120 on jeans and shirts for school-Total money spent ≤ 120. -(1)
3 pairs of jeans at $32 each-Money spent =$32 x 3 -(2)
Now x is the total dollar amount he can spend on shirts .

Hence ,total money spent on shirts found from (1) & (2) is ≤ (120 - $32 x 3).
So[spoiler],x ≤ (120 - 32 x 3)
i.e. (32 x 3 + x) ≤ 120 So,C[/spoiler]
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by shashank.ism » Fri Feb 19, 2010 9:29 am
sanju09 wrote:Marcus can spend no more than $120 on jeans and shirts for school. He buys 3 pairs of jeans at $32 each. If x represents the dollar amount he can spend on shirts, which of the following inequalities could be used to determine the possible values for x?
(A) (3) × 32 - x ≤ 120
(B) (3) × 32 - x ≥ 120
(C) (3) × 32 + x ≤ 120
(D) (3) × 32 + x ≥ 120
(E) x ≤ (3) × 32
spent on jeans = (3) × 32
cannot spend more than $120
so (3) × 32 + x≤ 120 Ans C
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by outreach » Fri Feb 19, 2010 10:19 am
(3) X 32 + x ≤ 120
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