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minimum value of the box?

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by uptowngirl92 » Fri Jul 24, 2009 5:33 pm
A cylinder with a radius of 5 stands upright in a closed cylinder box.If the volume of the cylinder is 100pi,what is the minimum value of the box?

Guys,I don't understand the concept.I got the height as 4 then reached a dead end.BTW,OA:D
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by prindaroy » Fri Jul 24, 2009 7:33 pm
The answer is 40/pi

First (pi)*5*5*h = 100pi, h = 4

so minimum vol. = diameter * diameter * height = 10*10*4 = 400

What is D?
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Re: minimum value of the box?

by gmat740 » Sun Jul 26, 2009 4:52 am
uptowngirl92 wrote:A cylinder with a radius of 5 stands upright in a closed cylinder box.If the volume of the cylinder is 100pi,what is the minimum value of the box?

Guys,I don't understand the concept.I got the height as 4 then reached a de@d end.BTW,OA:D
I never Heard any such thing :shock:

And What is the Option D??

Please check out the question again and re-post it.
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